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5k^2-42k-27=0
a = 5; b = -42; c = -27;
Δ = b2-4ac
Δ = -422-4·5·(-27)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-48}{2*5}=\frac{-6}{10} =-3/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+48}{2*5}=\frac{90}{10} =9 $
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